Theory Behind Nuclear Reaction
03 Jan 2009
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Theory Behind Nuclear Reaction Q&A
what are some of the ways a reactor works, and the theory behind nuclear reactions?
The report should include a description of the way a reactor works, and the theory behind nuclear reactions. Be sure to answer these questions: What are breeder reactors? How are they different from regular nuclear reactors? What are their advantages and disadvantages
Well, simply put, a conventional nuclear reactor splits a bunch of large atoms such as uranium into smaller ones. when the split is made particles called neutrons are released, and heat. The neutrons then zip around and impact other uranium atoms, splitting them, again releasing more neutrons and heat.
Were this not controlled, it would quickly escalate into a nuclear explosion. However control rods are inserted into the reaction chamber. These control rods absorb the neutrons and limit the reaction to a manageable level.
As I mentioned, this reaction produces heat. From here on out, it's a very conventional process. The heat is used to heat water circulating around the reactor into high pressure steam. This is used to turn steam turbines to produce electricity.
Don't know much about breeder reactors except the split atoms they produce can be processed into more fuel. Not sure how.
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No items matching your keywords were found.
Theory Behind Nuclear Reaction Videos
Our Friend the Atom 4 of 5 - Nuclear Reactions
Nuclear Weapons Test-Greenhouse-Item 45kt
Theory Behind Nuclear Reaction Q&A
Einstein's famous E = mc2?
I am using Einstein's famous E = mc2 E in this task. I understand the theory behind the equation (energy is equal to, etc.) but am unsure how applies to this assignment. For this assignment explains how this equation applies to nuclear fission. In its response to illustrate your explanation with an example, must distinguish between mass and mass number, and explain how a nuclear equation differs from a chemical equation. In addition to comparing the energy released the fission energy produced from a typical chemical reaction (eg oxidation of fossil fuels). It may be useful for you to consider the combustion of methane releases 50.1 kJ / g - much mass is lost to produce 50.1 kJ? I'm lost here, so please help me out by giving input and answer questions in this task! Thanks:) Thanks for your help, I'll take your advice and work through this question ... thanks again!
In a matter chemical process is changed and energy is released from bondage. In a nuclear process, continuous matter is converted into energy. Einstein's equation to calculate the amount of mass is lost when a certain amount of energy produced (in a nuclear rxn) Settlement of E = mc2, m = E / c ^ 2 = 50 100 J / (9e16 m2/s2) = 5.6e-13 kg = 5.6e-16 g in the amount of energy released by combustion of a gram of methane is equal to the amount of energy produced by only 5.6e-16 grams of material lost in a nuclear reaction. That is 1.8 billion times as much energy on a per gram!
Theory Behind Nuclear Reaction Q&A
Einstein's famous E = mc2?
I am using Einstein's famous E = mc2 E in this task. I understand the theory behind the equation (energy is equal to, etc.) but am unsure how applies to this assignment. For this assignment explains how this equation applies to nuclear fission. In its response to illustrate your explanation with an example, must distinguish between mass and mass number, and explain how a nuclear equation differs from a chemical equation. In addition to comparing the energy released the fission energy produced from a typical chemical reaction (eg oxidation of fossil fuels). It may be useful for you to consider the combustion of methane releases 50.1 kJ / g - much mass is lost to produce 50.1 kJ? I'm lost here, so please help me out by giving input and answer questions in this task! Thanks:) Thanks for your help, I'll take your advice and work through this question ... thanks again!
In a matter chemical process is changed and energy is released from bondage. In a nuclear process, continuous matter is converted into energy. Einstein's equation to calculate the amount of mass is lost when a certain amount of energy produced (in a nuclear rxn) Settlement of E = mc2, m = E / c ^ 2 = 50 100 J / (9e16 m2/s2) = 5.6e-13 kg = 5.6e-16 g in the amount of energy released by combustion of a gram of methane is equal to the amount of energy produced by only 5.6e-16 grams of material lost in a nuclear reaction. That is 1.8 billion times as much energy on a per gram!
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